cyanide19240
cyanide19240
04-07-2017
Mathematics
contestada
need help parabola and its vertex
Respuesta :
mileszsmith
mileszsmith
04-07-2017
[tex]y + 13 = 2(x - 1)^2[/tex]
use the equation: [tex](y_{2} - y_{1}) = m({x_{2} - x_{1})^2[/tex]
[tex](-11 + 13) = m(0 - 1)^2[/tex]
[tex]2 = m(1)^2[/tex]
[tex]m = 2[/tex]
[tex]y + 13 = 2(x - 1)^2[/tex]
substitute y for 0, since x-intercepts occur on the x-axis, or the line y = 0
[tex]0 + 13 = 2(x - 1)^2[/tex]
[tex]13 = 2(x - 1)^2[/tex]
[tex]13 = 2(x^2 - 2x + 1)[tex]
[tex]13 = 2x^2 - 4x + 2[/tex]
[tex]2x^2 - 4x - 15[/tex]
use the quadratic equation (can't type it out on brainly, if you don't know, look it up)
[tex]x = 1 - \sqrt{ \frac{13}{2} }, 1 + \sqrt{ \frac{13}{2} } [/tex]
The answer is: [tex](1 - \sqrt{ \frac{13}{2} },0)[/tex] and [tex](1 + \sqrt{ \frac{13}{2} },0)[/tex]
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