Respuesta :

konrad509
[tex](f \circ g)(x)=\sqrt{\dfrac{2(4+\sqrt x)}{5}}=\sqrt{\dfrac{8+2\sqrt x}{5}}\\\\ (f \circ g)(9)=\sqrt{\dfrac{8+2\sqrt 9}{5}}\\ (f \circ g)(9)=\sqrt{\dfrac{8+6}{5}}\\ (f \circ g)(9)=\sqrt{\dfrac{14}{5}}\\ (f \circ g)(9)=\dfrac{\sqrt{14}}{\sqrt5}\\ (f \circ g)(9)=\dfrac{\sqrt{70}}{5}\approx41,83 [/tex]

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