alejara4205 alejara4205
  • 01-12-2021
  • Mathematics
contestada

The half-life of radium is 1690 years. If 80 grams are present now, how much will be present in 870 years?
grams

Respuesta :

XxinstaPrincixX
XxinstaPrincixX XxinstaPrincixX
  • 01-12-2021

Answer:

A(t) = amount remaining in t years

= A0ekt, where A0 is the initial amount and k is a constant to be determined.

Since A(1690) = (1/2)A0 and A0 = 80,

we have 40 = 80e1690k

1/2 = e1690k

ln(1/2) = 1690k

k = -0.0004

So, A(t) = 80e-0.0004t

Therefore, A(430) = 80e-0.0004(430)

= 80e-0.172

≈ 67.4 g

Step-by-step explanation:

hope it helpful for you ❤️

Answer Link

Otras preguntas

simplify (1/x) + (1/(x+h)
Multiply these fractions (Lowest Terms) a) 2 x 3/4 b) 3 x 3/5 c) 4 x 1/3 d) 6 x 2/5 e) 1/2 x 1/4 f) 4/5 x 2/3 g) 5/6 x 3/4 h ) 1/10 x 2/3 i) 2 1/5 x 1/
How many flags are in this wolld ;)
simplify (1/x) + (1/(x+h)
How do I solve for x? X+6x=56
Is the E-CIG industry more "safe" than the actual tobacco companies? Why? If someone offered you E-CIGS than cigarettes would you say yes or no? Why?Full Paragr
Square of the complex number (i - 2)?
where does the shadow of the shuttle in space form?
Is the E-CIG industry more "safe" than the actual tobacco companies? Why? If someone offered you E-CIGS than cigarettes would you say yes or no? Why?Full Paragr
Convert the general form of the circle given into standard form. 2x^2 + 2y^2 - 20x - 8y + 50 = 0