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  • 02-10-2020
  • Mathematics
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what is the vertex of the parabola x^2+2x-8=y

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Anne0nymous
Anne0nymous Anne0nymous
  • 02-10-2020

Answer:

Vertex: (-1,-9)

Step-by-step explanation:

The vertex of an up-down facing parabola of the form y=ax^2+bx+c is x=-b/2a

Plug the values into the equation

a=1, b=2, c=-8

x=-2/(2*1)

Simplify

x=-1

Plug in x=-1 to find the y value

y=1(-1)^2 + 2(-1) + (-8)

y= -9

Then put them in a coordinate pair

Vertex: (-1,-9)

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