cristipopescud cristipopescud
  • 02-03-2014
  • Mathematics
contestada

How can i solve this
f:d->R
f(x)=x at power2/x-1

Respuesta :

crisforp
crisforp crisforp
  • 02-03-2014
x - 1 is not null => x is not 1 => D = R - {1};
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10+6b+8b simplified​